微分公式(まとめ)

$$\begin{eqnarray*} \left\{af(x)+bg(x)\right\}'&=&af'(x)+bg'(x)\\ \left\{f(x)\c... ...t}{dx}\\ \frac{dy}{dx}&=& \frac{1}{\displaystyle\frac{dx}{dy}} \end{eqnarray*}$$